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en:eingabe_der_schneckendaten:schneckenzonen [2025/05/05 10:16] – [Input of values] cschallen:eingabe_der_schneckendaten:schneckenzonen [2025/07/16 14:51] (aktuell) cschall
Zeile 14: Zeile 14:
   * A distinction is made between the worm clearance $δ$ (delta) and the flight depth $h$.   * A distinction is made between the worm clearance $δ$ (delta) and the flight depth $h$.
  
-The only exceptions here are the cylindrical and the conical shear part. For these two shear sections, the shear gap height from the base of the shear section to the cylinder surface must be entered.+The only exceptions here are the cylindrical and the conical shearing sections. For these two shear sections, the shear gap height from the base of the shear section to the cylinder surface must be entered.
  
 {{ :eingabe_der_schneckendaten:abb_kanalgeometrie_uebersicht_en.svg?nolink&800 |}}  {{ :eingabe_der_schneckendaten:abb_kanalgeometrie_uebersicht_en.svg?nolink&800 |}} 
Zeile 27: Zeile 27:
  
 Basically, the width of the channel results in Basically, the width of the channel results in
-$$b=t \cdot cos(\varphi) - e$$+$$b=\frac{t \cdot cos(\varphi) - i  \cdot e}{i}$$
 $$\text{with}$$ $$\text{with}$$
 $$tan(\varphi)=\frac{t}{\pi \cdot \overline{D}}$$ $$tan(\varphi)=\frac{t}{\pi \cdot \overline{D}}$$
 $$\text{and}$$ $$\text{and}$$
 $$\overline{D} = D-h$$ $$\overline{D} = D-h$$
-with the pitch $t$, the pitch angle $\varphi$, the flight width $e$, the nominal screw diameter $D$, the channel depth $h$ and the effective diameter $\overline{D}$. \\ +with the pitch $t$, the pitch angle $\varphi$, the flight width $e$, the nominal screw diameter $D$, the channel depth $h$ ,the number of channels $i$ and the effective diameter $\overline{D}$. \\ 
-In the figure above, however, areas that reduce the channel cross-section are marked in red. As REX/PSI always calculates with a simplified rectangular duct, the reduction of the duct cross-section is taken into account by a reduced duct width:+In the figure above, however, areas that reduce the channel cross-section are marked in red. As REX/PSI always calculates with a simplified rectangular channel, the reduction of the channel cross-section is taken into account by a reduced channel width:
 $$b_{effective}=\frac{b \cdot h-A_{radii,\gamma}}{h}$$ $$b_{effective}=\frac{b \cdot h-A_{radii,\gamma}}{h}$$
-Dividing the actual duct cross-section by the duct height $h$ results in the effective duct width.+Dividing the actual channel cross-section by the channel height $h$ results in the effective channel width.
  
-The duct cross-section $A_{radii,\gamma}$ is calculated as follows:+The channel cross-section $A_{radii,\gamma}$ is calculated as follows:
 $$A_{r<h,\gamma=90°} = \frac{r^2}{4} (4 - \pi)$$ $$A_{r<h,\gamma=90°} = \frac{r^2}{4} (4 - \pi)$$
  
Zeile 46: Zeile 46:
 ===== Notes on calculating the duct cross-section and volume =====  ===== Notes on calculating the duct cross-section and volume ===== 
  
-The calculation of the duct cross-section takes into account the actual duct width $b$, the effective duct width $b_{effective}$, the duct height $h$, the web width $e$ and the screw clearance $\delta$. The channel volume is made up of 2 areas:+The calculation of the channel cross-section takes into account the actual channel width $b$, the effective channel width $b_{effective}$, the channel height $h$, the flight width $e$ and the screw clearance $\delta$. The channel volume is made up of 2 areas:
  
-$$A_{ges.}=A_{Kanal}+A_\delta$$+$$A_{total}=A_{channel}+A_\delta$$
 $$\text{with}$$ $$\text{with}$$
 $$A_{channel} = b_{effective} \cdot h$$ $$A_{channel} = b_{effective} \cdot h$$
Zeile 56: Zeile 56:
 {{ :eingabe_der_schneckendaten:abb_kanalvolumen_en.svg?nolink&800 |}} {{ :eingabe_der_schneckendaten:abb_kanalvolumen_en.svg?nolink&800 |}}
  
-The duct volume is calculated by multiplying the duct cross-section by the unwound duct length $L_{duct}$:+The channel volume is calculated by multiplying the channel cross-section by the unwound channel length $L_{channel}$:
  
-$$V_{channel} = A_{ges.} \cdot L_{channel}$$+$$V_{channel} = A_{total} \cdot L_{channel}$$
 $$\text{with}$$ $$\text{with}$$
 $$L_{channel} = \frac{L_{zone}}{sin(\varphi)}$$ $$L_{channel} = \frac{L_{zone}}{sin(\varphi)}$$