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en:eingabe_der_schneckendaten:schneckenzonen [2025/05/05 10:26] – [Notes on calculating the duct cross-section and volume] cschallen:eingabe_der_schneckendaten:schneckenzonen [2025/07/16 14:51] (aktuell) cschall
Zeile 27: Zeile 27:
  
 Basically, the width of the channel results in Basically, the width of the channel results in
-$$b=t \cdot cos(\varphi) - e$$+$$b=\frac{t \cdot cos(\varphi) - i  \cdot e}{i}$$
 $$\text{with}$$ $$\text{with}$$
 $$tan(\varphi)=\frac{t}{\pi \cdot \overline{D}}$$ $$tan(\varphi)=\frac{t}{\pi \cdot \overline{D}}$$
 $$\text{and}$$ $$\text{and}$$
 $$\overline{D} = D-h$$ $$\overline{D} = D-h$$
-with the pitch $t$, the pitch angle $\varphi$, the flight width $e$, the nominal screw diameter $D$, the channel depth $h$ and the effective diameter $\overline{D}$. \\+with the pitch $t$, the pitch angle $\varphi$, the flight width $e$, the nominal screw diameter $D$, the channel depth $h$ ,the number of channels $i$ and the effective diameter $\overline{D}$. \\
 In the figure above, however, areas that reduce the channel cross-section are marked in red. As REX/PSI always calculates with a simplified rectangular channel, the reduction of the channel cross-section is taken into account by a reduced channel width: In the figure above, however, areas that reduce the channel cross-section are marked in red. As REX/PSI always calculates with a simplified rectangular channel, the reduction of the channel cross-section is taken into account by a reduced channel width:
 $$b_{effective}=\frac{b \cdot h-A_{radii,\gamma}}{h}$$ $$b_{effective}=\frac{b \cdot h-A_{radii,\gamma}}{h}$$
Zeile 56: Zeile 56:
 {{ :eingabe_der_schneckendaten:abb_kanalvolumen_en.svg?nolink&800 |}} {{ :eingabe_der_schneckendaten:abb_kanalvolumen_en.svg?nolink&800 |}}
  
-The duct volume is calculated by multiplying the duct cross-section by the unwound duct length $L_{duct}$:+The channel volume is calculated by multiplying the channel cross-section by the unwound channel length $L_{channel}$:
  
-$$V_{channel} = A_{ges.} \cdot L_{channel}$$+$$V_{channel} = A_{total} \cdot L_{channel}$$
 $$\text{with}$$ $$\text{with}$$
 $$L_{channel} = \frac{L_{zone}}{sin(\varphi)}$$ $$L_{channel} = \frac{L_{zone}}{sin(\varphi)}$$